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/* -*- Mode: c; c-basic-offset: 4; tab-width: 8; indent-tabs-mode: t; -*- */

/*

 *

 * Copyright © 2000 Keith Packard, member of The XFree86 Project, Inc.

 * Copyright © 2000 SuSE, Inc.

 *             2005 Lars Knoll & Zack Rusin, Trolltech

 * Copyright © 2007 Red Hat, Inc.

 *

 *

 * Permission to use, copy, modify, distribute, and sell this software and its

 * documentation for any purpose is hereby granted without fee, provided that

 * the above copyright notice appear in all copies and that both that

 * copyright notice and this permission notice appear in supporting

 * documentation, and that the name of Keith Packard not be used in

 * advertising or publicity pertaining to distribution of the software without

 * specific, written prior permission.  Keith Packard makes no

 * representations about the suitability of this software for any purpose.  It

 * is provided "as is" without express or implied warranty.

 *

 * THE COPYRIGHT HOLDERS DISCLAIM ALL WARRANTIES WITH REGARD TO THIS

 * SOFTWARE, INCLUDING ALL IMPLIED WARRANTIES OF MERCHANTABILITY AND

 * FITNESS, IN NO EVENT SHALL THE COPYRIGHT HOLDERS BE LIABLE FOR ANY

 * SPECIAL, INDIRECT OR CONSEQUENTIAL DAMAGES OR ANY DAMAGES

 * WHATSOEVER RESULTING FROM LOSS OF USE, DATA OR PROFITS, WHETHER IN

 * AN ACTION OF CONTRACT, NEGLIGENCE OR OTHER TORTIOUS ACTION, ARISING

 * OUT OF OR IN CONNECTION WITH THE USE OR PERFORMANCE OF THIS

 * SOFTWARE.

 */

#ifdef HAVE_CONFIG_H

#include 

#endif

#include 

#include 

#include "pixman-private.h"

static inline pixman_fixed_32_32_t

dot (pixman_fixed_48_16_t x1,

     pixman_fixed_48_16_t y1,

     pixman_fixed_48_16_t z1,

     pixman_fixed_48_16_t x2,

     pixman_fixed_48_16_t y2,

     pixman_fixed_48_16_t z2)

{

    /*

     * Exact computation, assuming that the input values can

     * be represented as pixman_fixed_16_16_t

     */

    return x1 * x2 + y1 * y2 + z1 * z2;

}

static inline double

fdot (double x1,

      double y1,

      double z1,

      double x2,

      double y2,

      double z2)

{

    /*

     * Error can be unbound in some special cases.

     * Using clever dot product algorithms (for example compensated

     * dot product) would improve this but make the code much less

     * obvious

     */

    return x1 * x2 + y1 * y2 + z1 * z2;

}

static uint32_t

radial_compute_color (double                    a,

		      double                    b,

		      double                    c,

		      double                    inva,

		      double                    dr,

		      double                    mindr,

		      pixman_gradient_walker_t *walker,

		      pixman_repeat_t           repeat)

{

    /*

     * In this function error propagation can lead to bad results:

     *  - discr can have an unbound error (if b*b-a*c is very small),

     *    potentially making it the opposite sign of what it should have been

     *    (thus clearing a pixel that would have been colored or vice-versa)

     *    or propagating the error to sqrtdiscr;

     *    if discr has the wrong sign or b is very small, this can lead to bad

     *    results

     *

     *  - the algorithm used to compute the solutions of the quadratic

     *    equation is not numerically stable (but saves one division compared

     *    to the numerically stable one);

     *    this can be a problem if a*c is much smaller than b*b

     *

     *  - the above problems are worse if a is small (as inva becomes bigger)

     */

    double discr;

    if (a == 0)

    {

	double t;

	if (b == 0)

	    return 0;

	t = pixman_fixed_1 / 2 * c / b;

	if (repeat == PIXMAN_REPEAT_NONE)

	{

	    if (0 <= t && t <= pixman_fixed_1)

		return _pixman_gradient_walker_pixel (walker, t);

	}

	else

	{

	    if (t * dr >= mindr)

		return _pixman_gradient_walker_pixel (walker, t);

	}

	return 0;

    }

    discr = fdot (b, a, 0, b, -c, 0);

    if (discr >= 0)

    {

	double sqrtdiscr, t0, t1;

	sqrtdiscr = sqrt (discr);

	t0 = (b + sqrtdiscr) * inva;

	t1 = (b - sqrtdiscr) * inva;

	/*

	 * The root that must be used is the biggest one that belongs

	 * to the valid range ([0,1] for PIXMAN_REPEAT_NONE, any

	 * solution that results in a positive radius otherwise).

	 *

	 * If a > 0, t0 is the biggest solution, so if it is valid, it

	 * is the correct result.

	 *

	 * If a < 0, only one of the solutions can be valid, so the

	 * order in which they are tested is not important.

	 */

	if (repeat == PIXMAN_REPEAT_NONE)

	{

	    if (0 <= t0 && t0 <= pixman_fixed_1)

		return _pixman_gradient_walker_pixel (walker, t0);

	    else if (0 <= t1 && t1 <= pixman_fixed_1)

		return _pixman_gradient_walker_pixel (walker, t1);

	}

	else

	{

	    if (t0 * dr >= mindr)

		return _pixman_gradient_walker_pixel (walker, t0);

	    else if (t1 * dr >= mindr)

		return _pixman_gradient_walker_pixel (walker, t1);

	}

    }

    return 0;

}

static uint32_t *

radial_get_scanline_narrow (pixman_iter_t *iter, const uint32_t *mask)

{

    /*

     * Implementation of radial gradients following the PDF specification.

     * See section 8.7.4.5.4 Type 3 (Radial) Shadings of the PDF Reference

     * Manual (PDF 32000-1:2008 at the time of this writing).

     *

     * In the radial gradient problem we are given two circles (c₁,r₁) and

     * (c₂,r₂) that define the gradient itself.

     *

     * Mathematically the gradient can be defined as the family of circles

     *

     *     ((1-t)·c₁ + t·(c₂), (1-t)·r₁ + t·r₂)

     *

     * excluding those circles whose radius would be < 0. When a point

     * belongs to more than one circle, the one with a bigger t is the only

     * one that contributes to its color. When a point does not belong

     * to any of the circles, it is transparent black, i.e. RGBA (0, 0, 0, 0).

     * Further limitations on the range of values for t are imposed when

     * the gradient is not repeated, namely t must belong to [0,1].

     *

     * The graphical result is the same as drawing the valid (radius > 0)

     * circles with increasing t in [-inf, +inf] (or in [0,1] if the gradient

     * is not repeated) using SOURCE operator composition.

     *

     * It looks like a cone pointing towards the viewer if the ending circle

     * is smaller than the starting one, a cone pointing inside the page if

     * the starting circle is the smaller one and like a cylinder if they

     * have the same radius.

     *

     * What we actually do is, given the point whose color we are interested

     * in, compute the t values for that point, solving for t in:

     *

     *     length((1-t)·c₁ + t·(c₂) - p) = (1-t)·r₁ + t·r₂

     *

     * Let's rewrite it in a simpler way, by defining some auxiliary

     * variables:

     *

     *     cd = c₂ - c₁

     *     pd = p - c₁

     *     dr = r₂ - r₁

     *     length(t·cd - pd) = r₁ + t·dr

     *

     * which actually means

     *

     *     hypot(t·cdx - pdx, t·cdy - pdy) = r₁ + t·dr

     *

     * or

     *

     *     ⎷((t·cdx - pdx)² + (t·cdy - pdy)²) = r₁ + t·dr.

     *

     * If we impose (as stated earlier) that r₁ + t·dr >= 0, it becomes:

     *

     *     (t·cdx - pdx)² + (t·cdy - pdy)² = (r₁ + t·dr)²

     *

     * where we can actually expand the squares and solve for t:

     *

     *     t²cdx² - 2t·cdx·pdx + pdx² + t²cdy² - 2t·cdy·pdy + pdy² =

     *       = r₁² + 2·r₁·t·dr + t²·dr²

     *

     *     (cdx² + cdy² - dr²)t² - 2(cdx·pdx + cdy·pdy + r₁·dr)t +

     *         (pdx² + pdy² - r₁²) = 0

     *

     *     A = cdx² + cdy² - dr²

     *     B = pdx·cdx + pdy·cdy + r₁·dr

     *     C = pdx² + pdy² - r₁²

     *     At² - 2Bt + C = 0

     *

     * The solutions (unless the equation degenerates because of A = 0) are:

     *

     *     t = (B ± ⎷(B² - A·C)) / A

     *

     * The solution we are going to prefer is the bigger one, unless the

     * radius associated to it is negative (or it falls outside the valid t

     * range).

     *

     * Additional observations (useful for optimizations):

     * A does not depend on p

     *

     * A < 0 <=> one of the two circles completely contains the other one

     *   <=> for every p, the radiuses associated with the two t solutions

     *       have opposite sign

     */

    pixman_image_t *image = iter->image;

    int x = iter->x;

    int y = iter->y;

    int width = iter->width;

    uint32_t *buffer = iter->buffer;

    gradient_t *gradient = (gradient_t *)image;

    radial_gradient_t *radial = (radial_gradient_t *)image;

    uint32_t *end = buffer + width;

    pixman_gradient_walker_t walker;

    pixman_vector_t v, unit;

    /* reference point is the center of the pixel */

    v.vector[0] = pixman_int_to_fixed (x) + pixman_fixed_1 / 2;

    v.vector[1] = pixman_int_to_fixed (y) + pixman_fixed_1 / 2;

    v.vector[2] = pixman_fixed_1;

    _pixman_gradient_walker_init (&walker, gradient, image->common.repeat);

    if (image->common.transform)

    {

	if (!pixman_transform_point_3d (image->common.transform, &v))

	    return iter->buffer;

	unit.vector[0] = image->common.transform->matrix[0][0];

	unit.vector[1] = image->common.transform->matrix[1][0];

	unit.vector[2] = image->common.transform->matrix[2][0];

    }

    else

    {

	unit.vector[0] = pixman_fixed_1;

	unit.vector[1] = 0;

	unit.vector[2] = 0;

    }

    if (unit.vector[2] == 0 && v.vector[2] == pixman_fixed_1)

    {

	/*

	 * Given:

	 *

	 * t = (B ± ⎷(B² - A·C)) / A

	 *

	 * where

	 *

	 * A = cdx² + cdy² - dr²

	 * B = pdx·cdx + pdy·cdy + r₁·dr

	 * C = pdx² + pdy² - r₁²

	 * det = B² - A·C

	 *

	 * Since we have an affine transformation, we know that (pdx, pdy)

	 * increase linearly with each pixel,

	 *

	 * pdx = pdx₀ + n·ux,

	 * pdy = pdy₀ + n·uy,

	 *

	 * we can then express B, C and det through multiple differentiation.

	 */

	pixman_fixed_32_32_t b, db, c, dc, ddc;

	/* warning: this computation may overflow */

	v.vector[0] -= radial->c1.x;

	v.vector[1] -= radial->c1.y;

	/*

	 * B and C are computed and updated exactly.

	 * If fdot was used instead of dot, in the worst case it would

	 * lose 11 bits of precision in each of the multiplication and

	 * summing up would zero out all the bit that were preserved,

	 * thus making the result 0 instead of the correct one.

	 * This would mean a worst case of unbound relative error or

	 * about 2^10 absolute error

	 */

	b = dot (v.vector[0], v.vector[1], radial->c1.radius,

		 radial->delta.x, radial->delta.y, radial->delta.radius);

	db = dot (unit.vector[0], unit.vector[1], 0,

		  radial->delta.x, radial->delta.y, 0);

	c = dot (v.vector[0], v.vector[1],

		 -((pixman_fixed_48_16_t) radial->c1.radius),

		 v.vector[0], v.vector[1], radial->c1.radius);

	dc = dot (2 * (pixman_fixed_48_16_t) v.vector[0] + unit.vector[0],

		  2 * (pixman_fixed_48_16_t) v.vector[1] + unit.vector[1],

		  0,

		  unit.vector[0], unit.vector[1], 0);

	ddc = 2 * dot (unit.vector[0], unit.vector[1], 0,

		       unit.vector[0], unit.vector[1], 0);

	while (buffer < end)

	{

	    if (!mask || *mask++)

	    {

		*buffer = radial_compute_color (radial->a, b, c,

						radial->inva,

						radial->delta.radius,

						radial->mindr,

						&walker,

						image->common.repeat);

	    }

	    b += db;

	    c += dc;

	    dc += ddc;

	    ++buffer;

	}

    }

    else

    {

	/* projective */

	/* Warning:

	 * error propagation guarantees are much looser than in the affine case

	 */

	while (buffer < end)

	{

	    if (!mask || *mask++)

	    {

		if (v.vector[2] != 0)

		{

		    double pdx, pdy, invv2, b, c;

		    invv2 = 1. * pixman_fixed_1 / v.vector[2];

		    pdx = v.vector[0] * invv2 - radial->c1.x;

		    /*    / pixman_fixed_1 */

		    pdy = v.vector[1] * invv2 - radial->c1.y;

		    /*    / pixman_fixed_1 */

		    b = fdot (pdx, pdy, radial->c1.radius,

			      radial->delta.x, radial->delta.y,

			      radial->delta.radius);

		    /*  / pixman_fixed_1 / pixman_fixed_1 */

		    c = fdot (pdx, pdy, -radial->c1.radius,

			      pdx, pdy, radial->c1.radius);

		    /*  / pixman_fixed_1 / pixman_fixed_1 */

		    *buffer = radial_compute_color (radial->a, b, c,

						    radial->inva,

						    radial->delta.radius,

						    radial->mindr,

						    &walker,

						    image->common.repeat);

		}

		else

		{

		    *buffer = 0;

		}

	    }

	    ++buffer;

	    v.vector[0] += unit.vector[0];

	    v.vector[1] += unit.vector[1];

	    v.vector[2] += unit.vector[2];

	}

    }

    iter->y++;

    return iter->buffer;

}

static uint32_t *

radial_get_scanline_wide (pixman_iter_t *iter, const uint32_t *mask)

{

    uint32_t *buffer = radial_get_scanline_narrow (iter, NULL);

    pixman_expand_to_float (

	(argb_t *)buffer, buffer, PIXMAN_a8r8g8b8, iter->width);

    return buffer;

}

void

_pixman_radial_gradient_iter_init (pixman_image_t *image, pixman_iter_t *iter)

{

    if (iter->iter_flags & ITER_NARROW)

	iter->get_scanline = radial_get_scanline_narrow;

    else

	iter->get_scanline = radial_get_scanline_wide;

}

PIXMAN_EXPORT pixman_image_t *

pixman_image_create_radial_gradient (const pixman_point_fixed_t *  inner,

                                     const pixman_point_fixed_t *  outer,

                                     pixman_fixed_t                inner_radius,

                                     pixman_fixed_t                outer_radius,

                                     const pixman_gradient_stop_t *stops,

                                     int                           n_stops)

{

    pixman_image_t *image;

    radial_gradient_t *radial;

    image = _pixman_image_allocate ();

    if (!image)

	return NULL;

    radial = &image->radial;

    if (!_pixman_init_gradient (&radial->common, stops, n_stops))

    {

	free (image);

	return NULL;

    }

    image->type = RADIAL;

    radial->c1.x = inner->x;

    radial->c1.y = inner->y;

    radial->c1.radius = inner_radius;

    radial->c2.x = outer->x;

    radial->c2.y = outer->y;

    radial->c2.radius = outer_radius;

    /* warning: this computations may overflow */

    radial->delta.x = radial->c2.x - radial->c1.x;

    radial->delta.y = radial->c2.y - radial->c1.y;

    radial->delta.radius = radial->c2.radius - radial->c1.radius;

    /* computed exactly, then cast to double -> every bit of the double

       representation is correct (53 bits) */

    radial->a = dot (radial->delta.x, radial->delta.y, -radial->delta.radius,

		     radial->delta.x, radial->delta.y, radial->delta.radius);

    if (radial->a != 0)

	radial->inva = 1. * pixman_fixed_1 / radial->a;

    radial->mindr = -1. * pixman_fixed_1 * radial->c1.radius;

    return image;

}