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| Rev | Author | Line No. | Line |
|---|---|---|---|
| 4349 | Serge | 1 | |
| 2 | /* |
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| 3 | * ==================================================== |
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| 4 | * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved. |
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| 5 | * |
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| 6 | * Developed at SunPro, a Sun Microsystems, Inc. business. |
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| 7 | * Permission to use, copy, modify, and distribute this |
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| 8 | * software is freely granted, provided that this notice |
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| 9 | * is preserved. |
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| 10 | * ==================================================== |
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| 11 | * |
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| 12 | */ |
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| 13 | |||
| 14 | |||
| 15 | * Method : |
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| 16 | * 1.Reduced x to positive by atanh(-x) = -atanh(x) |
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| 17 | * 2.For x>=0.5 |
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| 18 | * 1 2x x |
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| 19 | * atanh(x) = --- * log(1 + -------) = 0.5 * log1p(2 * --------) |
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| 20 | * 2 1 - x 1 - x |
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| 21 | * |
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| 22 | * For x<0.5 |
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| 23 | * atanh(x) = 0.5*log1p(2x+2x*x/(1-x)) |
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| 24 | * |
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| 25 | * Special cases: |
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| 26 | * atanh(x) is NaN if |x| > 1 with signal; |
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| 27 | * atanh(NaN) is that NaN with no signal; |
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| 28 | * atanh(+-1) is +-INF with signal. |
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| 29 | * |
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| 30 | */ |
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| 31 | |||
| 32 | |||
| 33 | |||
| 34 | |||
| 35 | |||
| 36 | |||
| 37 | static const double one = 1.0, huge = 1e300; |
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| 38 | #else |
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| 39 | static double one = 1.0, huge = 1e300; |
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| 40 | #endif |
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| 41 | |||
| 42 | |||
| 43 | static const double zero = 0.0; |
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| 44 | #else |
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| 45 | static double zero = 0.0; |
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| 46 | #endif |
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| 47 | |||
| 48 | |||
| 49 | double __ieee754_atanh(double x) |
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| 50 | #else |
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| 51 | double __ieee754_atanh(x) |
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| 52 | double x; |
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| 53 | #endif |
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| 54 | { |
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| 55 | double t; |
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| 56 | __int32_t hx,ix; |
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| 57 | __uint32_t lx; |
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| 58 | EXTRACT_WORDS(hx,lx,x); |
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| 59 | ix = hx&0x7fffffff; |
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| 60 | if ((ix|((lx|(-lx))>>31))>0x3ff00000) /* |x|>1 */ |
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| 61 | return (x-x)/(x-x); |
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| 62 | if(ix==0x3ff00000) |
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| 63 | return x/zero; |
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| 64 | if(ix<0x3e300000&&(huge+x)>zero) return x; /* x<2**-28 */ |
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| 65 | SET_HIGH_WORD(x,ix); |
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| 66 | if(ix<0x3fe00000) { /* x < 0.5 */ |
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| 67 | t = x+x; |
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| 68 | t = 0.5*log1p(t+t*x/(one-x)); |
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| 69 | } else |
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| 70 | t = 0.5*log1p((x+x)/(one-x)); |
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| 71 | if(hx>=0) return t; else return -t; |
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| 72 | } |
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| 73 | |||
| 74 | |||
| 75 | > |